Question

A particle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second. What is the maximum height of the particle?

Answer 1

 the answer  is   448 feet :))

Answer 2

482.25 feet

Explanation:

To solve this question, we will need to use one of the equations of linear motion. To decide which one we should use, let us first write down what we have

initial height = 160 feet

initial speed = 144 feet/second

acceleration = g = -32.17405 ft/s² negative because it is opposite the direction

of motion

maximum height = ? That is what we are asked to find

so the equation we can use is

`v^(2) = u^(2) +2as\\(0)^(2) = 144^(2) +2(-32.17405)s\\s = 322.25 feet`

But remember the initial height was 160 feet.

So maxiumum = 322.25 feet + 160 feet

= 482.25 feet