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What is the completely factored form of 25x4 – 16y2?

User Djb
by
7.7k points

2 Answers

3 votes
das is difference of 2 perfect squares
remember
a^2-b^2=(a-b)(a+b)

so
25x^4=(5x^2)^2
16y^2=(4y^2)

(5x^2)^2-(4y)^2=(5x^2-4y)(5x+4y)
cannot be factored further
User Desirea
by
8.2k points
2 votes

Answer:


(5x^(2) + 4y),(5x^(2) - 4y)

Explanation:

Given :
25x^(4) - 16y^(2).

To find : What is the completely factored form .

Solution : We have given
25x^(4) - 16y^(2).

We can write it as


(5x^(2))^(2) - (4y)^(2)

Using the identity
a^(2) - b^(2) = (a+b) (a-b).

Here, a =
(5x^(2)) , b =
(4y).

Then ,


(5x^(2))^(2) - (4y)^(2) =
(5x^(2) + 4y)  , (5x^(2) - 4y)

Therefore,
(5x^(2) + 4y),(5x^(2) - 4y)

User Enmanuel
by
7.7k points