Question

A 10.5 L balloon contains helium gas at a pressure of 640 mmHg . What is the final pressure, in millimeters of mercury, of the helium gas at each of the following volumes if there is no change in temperature and amount of gas?Part A: 13700 mL

Answer 1

Step 1

Boyle's Law states that the pressure exerted by a gas is inversely proportional to the volume occupied by it at a constant mass and temperature.

Mathematically:

`P1\text{ x V1 = P2 x V2}`

P1 = pressure 1

V1 = volume 1

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P2 = pressure 2

V2 = volume 2

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Step 2

Information provided:

V1 = 10.5 L

P1 = 640 mmHg

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P2 = unknown

V2 = 13700 mL

(1 L = 1000 mL => 13700 mL x (1 L/1000 mL) = 13.7 L

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Step 3

From step 1, P2 is found as follows:

P1 x V1 = P2 x V2

(P1 x V1)/V2 = P2

(640 mmHg x 10.5 L)/13.7 L = 491 mm Hg approximately

Answer: P2 = 491 mmHg