Question

In the function F(t)=50(1.2)^t, what is the rate of change

a. 20%decay
b. 2% growth
c.2%decay
d.20%growth

Answer 1

The answer to your question is d.20%growth
I hope this helps

Answer 2

Answer: d.20%growth

Explanation:

The given function
`F(t)=50(1.2)^t` is similar to the exponential growth function
`y=A(1+r)^t`, where A is the initial amount , r is the rate of growth and t is the time period.

In the given function A=50

`(1+r)=(1.2)\\\Rightarrow(1+r)=(1+0.2)\\\Rightarrow\ r=0.2\\\Rightarrow\r=0.2*100\\\Rightarrow\ r=20\%`

Hence, in the given F(t), the rate of change = 20%growth.