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F(x) = log10 (x) + 5

1 Answer

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Answer:

Find the asymptotes.

Set the argument of the logarithm equal to zero.

x+5=0 . Subtract 5

from both sides of the equation. x=−5

The vertical asymptote occurs at x=−5

Vertical Asymptote: x=−5

Find the point at x=−4

Replace the variable x with −4

in the expression.

f(−4)=log((−4)+5)

Simplify the result. Add −4 and 5

f(−4)=log(1) Logarithm base 10 of 1 is 0

f(−4)=0

The final answer is 0

Convert 0 to decimal. y=0

Find the point at x=5. Replace the variable x with 5

in the expression.

f(5)=log((5)+5)

Simplify the result. Convert 1 to decimal. y=1

Find the point at x=−3

Replace the variable x with −3

in the expression.

f(−3)=log((−3)+5)

Simplify the result.

log(2) . Convert log(2) to decimal. y=0.30102999

The log function can be graphed using the vertical asymptote at x=−5 and the points (−4,0),(5,1),(−3,0.30102999)

Vertical Asymptote: x=−5

x y

−4 0

−3 0.301

5 1

Explanation:

F(x) = log10 (x) + 5-example-1
User Jeremy Morren
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