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Instructions:Select the correct answer.

Which sequence is not equivalent to the others?
a reflection across the y-axis, followed by a reflection across the x-axis, and then a 90° clockwise rotation about the origin
a 90° clockwise rotation about the origin and then a 180° rotation about the origin
a reflection across the x-axis, followed by a 90° counterclockwise rotation about the origin, and then a reflection across the x-axis
a 90° counterclockwise rotation about the origin
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User Sahil M
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2 Answers

4 votes
the second one is correct
User Luke Mills
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9.0k points
3 votes

Answer:

The correct option is 3.

Explanation:

Option 1,

A reflection across the y-axis,


P(x,y)\rightarrow P_1(-x,y)

then reflection across the x-axis


(x,y)\rightarrow (x,-y)


P_1(-x,y)\rightarrow P_2(-x,-y)

and then a 90° clockwise rotation about the origin.


(x,y)\rightarrow (y,-x)


P_2(-x,-y)\rightarrow P_3(-y,x)

So the image of P(x,y) is P'(-y,x).

Option 2,

A 90° clockwise rotation about the origin


P(x,y)\rightarrow P_1(y,-x)

and then a 180° rotation about the origin.


(x,y)\rightarrow (-x,-y)


P_1(y,-x)\rightarrow P_2(-y,x)

So the image of P(x,y) is P'(-y,x).

Option 3,

A reflection across the x-axis,


P(x,y)\rightarrow P_1(x,-y)

Followed by a 90° counterclockwise rotation about the origin.


(x,y)\rightarrow (-y,x)


P_1(x,-y)\rightarrow P_2(y,x)

and then a reflection across the x-axis.


(x,y)\rightarrow (x,-y)


P_2(y,x)\rightarrow P_3(y,-x)

So the image of P(x,y) is P'(y,-x).

Option 4,

A 90° counterclockwise rotation about the origin


P(x,y)\rightarrow P_1(-y,x)

So the image of P(x,y) is P'(-y,x).

The third sequence is not equivalent to the others. Therefore the correct option is 3.

User Paulraj
by
8.6k points

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