Question

Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the solution is made up of a 20% acid solution. The remaining three-quarters is made up of a solution of unknown concentration, c.

Which equation can be used to determine c, the unknown concentration?

A. 30c + 10(0.2) = 40(0.32)
B. (c) + (0.2) = 40(0.32)
C. (c)( (0.2)) = 40(0.32)
D. 30(c)(10(0.2)) = 40(0.32)

Answer 1

Explanation:

nswer:

Solution 1 : 10mL with 20% acid

Solution 2 : 30mL with x% acid

Solution 3 : 40mL with 32% acid

Explanation:

Since solution 1 + solution 2 = solution 3, let us substitute the given values we have:

10(0.2) + 30(x) = 40(0.32)

2 + 30x = 12.8

To solve for the unknown concentration x, we subtract 2 from both sides:

2 + 30x - 2 = 12.8 - 2

30x = 10.8

Dividing both sides by 30:

30x/30 = 10.8/30

x = 0.36

Therefore the unknown solution is 36% acid.

Answer 2

The 40 ml solution is said to be created from 10 ml and 30 ml solutions. In mixture problems, we equate the final mixture to its compositions given the concentration for each. A 10 ml has 20% acid and the 30 ml has C (unknown). We can write the total liters for 10 ml as 10(.2) and 30(c) for the 30 ml. when two solutions were added, it should be equal to 40ml with 32% acid. Therefore, it should be written as 10(.2) + 30(c) = 40(.32). The answer is A