Question

Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral A'B'C'D'. The coordinates of A' are ( , ).

The reflected quadrilateral A'B'C'D' is then translated 3 units right and 2 units up to form quadrilateral A"B"C"D". The coordinates of A" are ( , ).

Answer 1

Answer: A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

Step-by-step explanation: When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:

A(-5,-3); A'(-5,+3)

B(-6,-1); B'(-6,+1)

C(-3,-1); C'(-3,+1)

D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'

are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)

B'(-6,+1) ==>B"(-3,1)

C'(-3,+1) ==>C"(0,1)

D'(-2,+3) ==>D"(1,3)

Answer 2

1) A(-5,-3); B(-6,-1); C(-3,-1) ; D(-2,-3)

When a refection is done about x-axis, the values of the abscise x remain identical & the value of ordinate just change their signs:
A(-5,-3); A'(-5,+3)
B(-6,-1); B'(-6,+1)
C(-3,-1); C'(-3,+1)
D(-2,-3); D'(-2,+3)

2) A'B'C'D' is translated 3 UNITS RIGHT, that means the ordinated of A'B'C'D'
are the same but the abscises have been increased by 3 UNITS ;

A'(-5,+3) ==>A"(-2,3)
B'(-6,+1) ==>B"(-3,1)
C'(-3,+1) ==>C"(0,1)
D'(-2,+3) ==>D"(1,3)