Question

Which lewis electron dot diagram represents a boron atom in the ground state

Answer 1

Boron is  an element in the periodic table with a symbol B 5 is its atomic number. Its atomic mass is 10.81 grams per mole. The electron configuration of the said atom is [He] 2s2 2p1 which means that it has one pair of electrons, one unshared electron and 2 unpaired electrons. So in order for it to be stable, it needs 5 electrons.

Answer 2

Answer : The Lewis-dot structure of boron atom is shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.

In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.

The given atom is, boron (B)

The electronic configuration of nitrogen atom is,

`1s^22s^22p^1`

As we know that boron has '3' valence electrons.

The Lewis-dot structure of boron atom is shown below.