Question

Three women and three children wish to cross a river in a canoe that will hold only one woman and or two children. they can all row on their own but no one can swim. if a onne way trip in the canoe takes ten minutes, what is the minimum time in which all six people can cross the river

Answer 1

The minimum time for all six people to cross the river is 50 minutes.

Step-by-step explanation:

The key to solving this problem is to come up with the optimal combination of people to row the canoe across the river in the shortest time possible. Since the canoe can hold either one woman or two children, we need to figure out the best way to ferry everyone across without wasting any time. Here's how we can do it:

1. Two children row across the river, taking 10 minutes.
2. One child returns with the canoe, taking 10 minutes.
3. Two women row across the river, taking 10 minutes.
4. One child returns with the canoe, taking 10 minutes.
5. Two children row across the river again, taking 10 minutes.

So, the minimum time in which all six people can cross the river is 50 minutes.

Answer 2

(w,k)
that is amount of women and children lefton original side


ok, first realize you must get children across first because who will row the boat back

first trip: 10min, 2 children across, (3,1)
2nd trip: 20min, 1 kid cross back (3,2)
3rd trip: 30min, 2 kids cross (3,0)
4th trip: 40 min, 1 kid cross baack (3,1)
5th trip: 50 min, 1 woman cross (2,1)
6th trip: 60 min, 1 kid cross back (2,2)
7th trip: 70 min, 1 woman cross (1,2)
8th trip: 80 min, 1 kid cross back (1,1)
9th trip: 90 min, 1 woman cross (0,1)
10th trip: 100min, 1 kid cross back (0,2)
11th trip: 110 min, 2 kids cross back (0,0)

min time is 110 mins or 1hr 50min