Question

A researcher wants to make a solution of agcl and water at 75 °c. for solid agcl at 75°c, ksp = 1.5 x 10-5.

a. calculate the free energy change associated with making a saturated solution of agcl in water at 75 °c.
b. how many grams of agcl will dissolve in 1.0 l of water at 75 °c?'

Answer 1

A.)
dG = -(0.008314)(348K) (1.5 * 10-5)
dG = -(0.008314)(348K (-11.107)
dG = 32 kJ/mol (rounded from 32.14)
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B.)
AgCl(s) >>>> Ag+ and Cl-
Ksp = {Ag+}{Cl-}
1.5 * 10-5 = {Ag+}{Cl-}
1.5 * 10-5 = {X}{X}
X2 = 1.5 x 10-5
X={Ag+}{Cl-}
Sol / AgCl = 3.873E-3 litres/moles
(3.873E-3 moles AgCl/Litre) (143.32 g AgCl / mol)= 0.56g AgCl