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Find the number of permutations of the first 8 letters of the alphabet taking four letters at a time.

a.1680
b.56
c.6720
d.109

User Drl
by
6.8k points

2 Answers

4 votes
The answer you are looking for is A.1608
User Yumba
by
6.2k points
2 votes

Answer: a.1680

Explanation:

The number of permutations of n things taking m at a time is given by :-


P^n_m=(n!)/((n-m)!)

Similarly, the number of permutations of the first 8 letters of the alphabet taking four letters at a time will be :-


P^8_4=(8!)/((8-4)!)\\\\=(8*7*6*5*4!)/(4!)\\\\=1680

Hence, the number of permutations of the first 8 letters of the alphabet taking four letters at a time =1680

User Rene Schulte
by
6.7k points
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