Question

Suppose that is an angle with cos gamma = - 9/14 andy is not in the third quadrant. Compute the exact value of an*gamma You do not have to rationalize the denominator.

Answer 1

Answer:
`\tan\gamma=-1.192`

Step-by-step explanation:

Given that

`\begin{gathered} \cos\gamma=-(9)/(14) \\ \\ \gamma=\cos^(-1)(-(9)/(14))=130 \end{gathered}`

Now,

`\tan\gamma=\tan(130)=-1.192`