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A wagon filled with groceries weighing 36 pounds begins to roll down a hill having an incline of 300. What force is required to keep the wagon from sliding down the hill?

2 Answers

3 votes

~150 J

thats what i came up with...this question is quite simple
User Ravi Ram
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5 votes

Answer:

18 lbs

Explanation:

We are given that a wagon filled with groceries weighing 36 pounds begins to roll down a hill having an incline
30^(\circ).

We have to find the value of force required to keep the wagon from sliding down the hill

Weight of wagon filled with groceries=36 pounds


\theta=30^(\circ)

Then, the force is required=
mg sin\theta

Substitute the values then we get


F=36 sin 30^(\circ)

F=18 lbs

Hence, the force required to keep the wagon from sliding down the hill=18 lbs

User Niceman
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7.7k points