Register
in order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00 kg of water?
212k views
3 votes
in order to prepare a 0.523 m aqueous solution of potassium iodide, how many grams of potassium iodide must be added to 2.00 kg of water?

User Aric
by
5.9k points

1 Answer

4 votes
M = amount of the solute / mass of the solvent

0.523 = x / 2.00

x = 0.523 * 2.00

x = 1,046 moles

molar mass KI = 166.0028 g/mole

Mass = 1,046 * 166.0028

Mass ≈ 173.63 g
User Gagarwa
by
6.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

7.3m questions

9.7m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Key facts of covalent bonding
How do you decide whether an observed property of matter is a physical or a chemical property?
Consider the unbalanced equation for the combustion of hexane: 2C6H14(g)+19O2(g)→12CO2(g)+14H2O(g) Determine how many moles of O2 are required to react completely with 7.9 moles C6 H14 .
Link Copied!