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A buret was improperly read to 1 decimal place giving a reading of 27.2 mL. If the actual volume is 27.26 mL, what is the percent error caused by this mistake?

User Phiter
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2 Answers

3 votes

Answer: 0.22 %

Step-by-step explanation:

Actual volume : 27.26 ml

Volume measured : 27.2 ml


\% error=\frac{\text{theoretical value}}* 100

Putting the values we get:


\%=\frac\text(27.26- 27.2){27.26}* 100=0.22\%

Thus the percent error caused by this mistake is 0.22%

User DaSch
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4 votes
Percent error can be calculated by the difference of the theoretical value and the measured value divided by the theoretical value multiplied by 100 percent.

% error = 27.26 - 27.2 / 27.26 x100
% error = 0.22%

A value close to zero would mean that the measured value is more or less near the actual value.
User Skiminok
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