Line A
initial height 2 feet
when x=1
height is 6 ft
y= height
x= minutes
y=mx+b
in our case
b= initial height
then we need to find m
y=6
x=1
b=2
6=m(1)+2
we isolate the m
m=6-2
m=4
The equation that represents line A is
y=4x+2
Then for x=4
y=4(4)+2
y=18
Line A height is 18 ft when x=4
Line B
initial height 3 ft
when x=1 the height of line B is 3 1/2
the form of the equation of line B is
y=mx+b
b is the initial height
y= height
x= minutes
If
x=1
y=3 1/2 ft
3 1/2= m(1)+3
m=1/2
The equation of the line is
y=1/2 x+3
if x=4
y=1/2 (4)+3
y=5
Line B height is 5ft when x=4