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Find the distance between the points (-7, 5) and (4, 1). 1. 5 2. square root of 137 3. square root of 157
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1 vote
Find the distance between the points (-7, 5) and (4, 1).

1. 5
2. square root of 137
3. square root of 157

User Josh Townzen
by
7.9k points

2 Answers

6 votes

\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -7}}\quad ,&{{ 5}})\quad % (c,d) &({{ 4}}\quad ,&{{ 1}}) \end{array}\qquad % distance value d = \sqrt{({{ 4}}-{{ (-7)}})^2 + ({{ 1}}-{{ 5}})^2} \\\\\\ d=√((4+7)^2+(1-5)^2)
User Penguino
by
7.8k points
4 votes
2 because the square root is 12 and the distance is 12 units
User Daniyal Lukmanov
by
9.1k points
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