Question

Find the vertex of: y=6(x-1)2-8
(x,y)

Answer 1

`\bf \qquad \textit{parabola vertex form}\\\\ \begin{array}{llll} y=a(x-{{ h}})^2+{{ k}}\\\\ x=a(y-{{ k}})^2+{{ h}} \end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\ -----------------------------\\\\ \begin{array}{lllcll} y=&6(x-&1)^2&-8\\ &\uparrow &\uparrow &\uparrow \\ &a&h&k \end{array}`