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2 votes
Which line is parallel to the line that passes through the points (2, –5) and (–4, 1)? a. y=-x-5

b. y=-2/3x+3
c. y=2/3x-2
d. y=x+5
please explain

2 Answers

3 votes

\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 2}}\quad ,&{{ -5}})\quad % (c,d) &({{ -4}}\quad ,&{{ 1}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-(-5)}{-4-2} \\\\\\ m\implies \cfrac{1+5}{-6}\implies \cfrac{6}{-6}\implies -1

now, a line parallel to one that has those two points, will also have the same slope, this line has a slope of -1

let's take a peek at
\bf \begin{array}{llll} y=&-x&-5\\ y=&-1x&-5\\ &\quad \uparrow &\quad \uparrow \\ &slope&y-intercept \end{array}

notice the slope of that one... recall your y = mx+b, slope-intercept form
User EvilTak
by
9.1k points
4 votes
The answer is D
the answer is D
User Nuzhdin Vladimir
by
8.5k points

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