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A student collected data for a spring-mass systemGiven:g = 10 m/s/sSpring is considered to be idealSpring Constant = 80 N/mData:Mass of object = .50 kgAmplitude of oscillation = 0.3 mCalculate the maximum velocity of the mass.4.2 m/sThe correct answer is not shown3.8 m/s4.0 m/s4.9 m/s4.7 m/s4.5 m/s

User Duck Dodgers
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1 Answer

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23 votes

This question is related to angular frequency of oscillation

Given,

g=10 m/sĀ²

k=80 N/m

m=0.5 kg

A=0.3 m

The angular frequency of oscillation of mass is given by


\omega=\sqrt{(k)/(m)}

Putting the values in the equation above


\omega=\sqrt{(80)/(0.5)}=āˆš(160)

The maximum speed of the mass is given by


v_(max)=\omega A=āˆš(160)*0.3

Result: The correct option will be A which is 3.8 m/s