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Factor completely: 81x4 – 81 (9x2 + 9)(9x2 – 9) (3x + 3)2(3x – 3)2 (3x + 3)(3x – 3) (9x2 + 9)(3x + 3)(3x – 3)

Factor completely: 81x4 – 81 (9x2 + 9)(9x2 – 9) (3x + 3)2(3x – 3)2 (3x + 3)(3x – 3) (9x2 + 9)(3x + 3)(3x – 3)
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Factor completely: 81x4 – 81 (9x2 + 9)(9x2 – 9) (3x + 3)2(3x – 3)2 (3x + 3)(3x – 3) (9x2 + 9)(3x + 3)(3x – 3)

User Eylen
by
7.9k points

2 Answers

4 votes
81 is the same as 3⁴.

Thus, we can write it as:

(3x)^(4) - 3^(4)

= [(3x)^(2)]^(2) - [3^(2)]^(2)

= [(3x)^(2) - 3^(2)][(3x)^(2) + 3^(2)]

= (3x - 3)(3x + 3)[(3x)^(2) + 3^(2)]

= (3x - 3)(3x + 3)(9x^(2) + 9)
User DrGodCarl
by
7.7k points
3 votes
Last voice (9x^2+9)(3x-3)(3x+3)
User Ankur Mukherjee
by
7.7k points
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