Question

Volume of a pyramid: v = 1/3(area of base x (height surface area of a pyramid: a = 1/2(perimeter of base x (slant height + (area of base a pyramid has a height of 4.7 in. and a slant height of 5.2 in. its base is a square with sides of 3.5 in. find the pyramid's volume and surface area.

Answer 1

V= 1/3 LWH
1/3(3.5)(3.5)(4.7)
19.19 in ^3

SA= 2(3.5)(5.2)+(3.5)^2
48.65 in^2

Answer 2

Volume of Pyramid
`= 19.19 in^3\\`

Surface Area of Pyramid
`= 48.65 in^2\\\\`

Explanation:

Given

Height of the pyramid
`= 4.7 in\\`

Slant height of the pyramid =
`5.2 in\\`

Base of pyramid is a square with side
`= 3.5 in\\`

Volume of the pyramid

`= (1)/(3) * (3.5 * 3.5) * (4.7)\\= 19.19 in^3\\`

Surface area of the pyramid

`=( (1)/(2) * (4 * 3.5) * 5.2) + ( 3.5 * 3.5)\\= 48.65 in^2\\`