Question

Calculate the instantaneous rate of change at x = -1

Answer 1

The function that describes the graph above looks like this:

`x^2-2x=0`

The rate of change at a particular moment is the same as the value of the derivative at a particular point. So, let's find a derivative of your function:

`f'(x)=(x^2-2x)'=2x-2`

Now, let's replace
`x` variable with given value
`(-1)`:

`f'(-1)=2*(-1)-2=-4`

Solution:the instantaneous rate of change at
`x = -1` is -4.