Question

BC has endpoints B(5,9) and C(-4,-5)find the coordinates of the midpointBC

Answer 1

Let's mark our midpoint with letter
`M`. Here is the formula for finding it:

`M(x_(m),y_(m))=M( (x_(b)+x_(a))/(2), (y_(b)+y_(a))/(2) )`

Now let's replace formula variables with corresponding values and calculate our midpoint:

`M(x_(m),y_(m))=M( (5+(-4))/(2), (9+(-5))/(2) )=M( (5-4)/(2), (9-5)/(2) )=`

`=M( (1)/(2), (4)/(2) )=M(0.5,2)`

So midpoint of
`BC` is
`M(0.5,2)`.

Answer 2

We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.

I hope this helps.