Question

This math problem seemed simple but it’s giving me so much trouble

Answer 1

Answer:smaller is 6 larger is 8

Step-by-step explanation:

Answer 2

Given:

One number is 2 less than a second number.

Twice the second number is 2 less than 3 times the first.

Required:

We need to find the smaller number and the larger number,

Step-by-step explanation:

Let x be the first number and y be the second number.

The first number is 2 less than the second number.

`x=y-2`

Twice the second number is 2 less than 3 times the first.

`twice\text{ the second number means 2y.}`
`three\text{ times the first number means 3x.}`

Twice the second number is 2 less than 3 times the first.

`2y=3x-2`

Substitute x =y-2 in the equation.

`2y=3(y-2)-2`

`2y=3y-3*2-2`

`2y=3y-6-2`

`2y=3y-8`

Solve for y.

`3y-2y=8`

`y=8`

Substitute y =8 in the equation x =y-2, we get

`x=8-2`
`x=6`

Final answer:

`The\text{ smaller number is 6.}`

`The\text{ larger number is 8.}`