Question

What is the inverse of h?

h(x) = 6x + 1

A) h^-1(x) = 6x - 1
B) h^-1(x) = 6x + 1
C) h^-1(x) = x/6 - 1
D) h^-1(x) = 1/6 (x - 1)

Answer 1

to find the inverse of f(x),,

replace f(x) with y
switch x and y
solve for y
replae y with f infverse or f^-1(x)

h(x)=6x+1
replace
y=6x+1
switch
x=6y+1
solve
x-1=6y
(x-1)/6=y
replace
h^-1(x)=(x-1)/6


D is answer

Answer 2

Answer: Option 'D' is correct.

Explanation:

Since we have given that

`h(x)=6x+1\\`

We need to find the inverse of h .

Let,

`h(x)=y`

the our equation becomes,

`y=6x+1\\\\y-1=6x\\\\(y-1)/(6)=x`

Now, interchange x with y :

`(x-1)/(6)=y`

so, our inverse of h will be

`h^(-1)(x)=(x-1)/(6)`

Hence, Option 'D' is correct.