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If m^2-5/2m=-11/2,m=

User Andysando
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2 Answers

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The answer is m = ( 5 ± 3i√7) / 4
User Paul J Abernathy
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7 votes

Answer: The required value of m is


m=(5+√(63)i)/(4),~~~~~(5-√(63)i)/(4).

Step-by-step explanation: We are given to find the vale of m if :


m^2-(5)/(2)m=-(11)/(2)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

The given equation is a quadratic one, so we will be using the formula for the solution of a quadratic equation
ax^2+bx+c=0,~a\\eq 0 as follows :


x=(-b\pm√(b^2-4ac))/(2a).

From equation (i), we have


m^2-(5)/(2)m=-(11)/(2)\\\\\\\Rightarrow 2m^2-5m+11=0\\\\\Rightarrow x=(-(-5)\pm√((-5)^2-4*2*11))/(2*2)\\\\\\\Rightarrow x=(5\pm√(25-88))/(4)\\\\\\\Rightarrow x=(5\pm√(-63))/(4)\\\\\\\Rightarrow x=(5\pm√(63)i)/(4).

Thus, the required value of m is


m=(5+√(63)i)/(4),~~~~~(5-√(63)i)/(4).

User Mike Harrison
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