48.2k views
5 votes
A bag contains tiles with the letters a-r-i-t-h-m-e-t-i-c. amelia chooses a tile without looking and doesn't replace it. she chooses a second tile without looking. what is the probability that she will choose the letter t both times

User Barnyr
by
8.4k points

1 Answer

6 votes
Sample space={A,R,I,T,H,M,E,T,I,C}

1ST (Choosing T) ==> P(1st draw) = 2/10 = 1/5 = 0.2

2ND (Choosing again a T) ==> P(2nd draw) = 1/9 = 0.11

Since it's a conditional probability then P (1st T AND 2nd T) = 0.2 x 0.11 =0.022
User Jzelar
by
7.4k points