Question

If each resistor in the circuit shown is 5.0 Ω and the battery is 12.0 V, what does the first ammeter (A1) read? A. 0.12 V B. 0.48 V C. 0.96 V D. .24 V

Answer 1

Rt= R1+R4+R23

R23 = 5/2 = 2.5 Ω

Rt= 5+5+2.5= 12.5Ω

I = U/R = 12/12.5=0.96 A

Answer C, A not V

Answer 2

The first ammeter reads 0.96 A.

Step-by-step explanation:

From the attached figure,

Resistance of all resistors, R₁ = R₂ = R₃ = R₄ = 5 Ω

Voltage of the battery, V = 12 V

First we will find the total resistance of the circuit,

R₂ and R₃ are in parallel. So,

`(1)/(R_(23))=(1)/(R_2)+(1)/(R_3)`

`R_(23)=2.5\ \Omega`

Now R₁, R₂₃ and R₄ are in series.

So,
`R_(eq)=5+5+2.5`

`R_(eq)=12.5\ \Omega`

Now we have to find the current across the first ammeter.

`I=(V)/(R_(eq))`

`I=(12\ V)/(12.5\ \Omega)`

So, I = 0.96 A

Hence, the correct option is (c) " 0.96 A"