Question

The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is units, and the area of the triangle is square units. (Hint: Use the Pythagorean theorem.)

Answer 1

The hypotenuse length is √(4*4 + 3*3) = 5 (not √7 I suppose)
The area is base*half height = 4*3/2 = 6.

In short, I don't think complex numbers really interfere here.