Question

How many moles of a gas sample are in a 20.0 L container at 373 K and 203 kPa? The gas constant is 8.31 L-kPa/mol-K. 0.33 moles 3.05 moles 1.30 moles 0.65 moles

Answer 1

we need to use the ideal gas formula--> PV= nRT
P, pressure= 203 kPa
V, volume= 20.0 Liters
n, moles= ?
R, constant= 8.31 L-kPa/mol-K
T, temperature= 373 K

now, lets plug these values into the formula

(203)(20.0)= (n)(8.31)(373)

n= 1.31 moles

Answer 2

Answer: The number of moles of the gas is 1.31 mol.

Step-by-step explanation:

To calculate the number of moles of gas, we use the equation given by ideal gas, which is:

`PV=nRT`

where,

P = pressure of the gas = 203 kPa

V = volume of the gas = 20 L

n = Number of moles of gas = ? mol

R = Gas constant =
`8.31\text{L kPa }mol^(-1)K^(-1)`

T = temperature of the gas = 373 K

Putting values in above equation, we get:

`203kPa* 20L=n* 8.31\text{L kPa }* 373K\\\\n=1.31mol`

Hence, the number of moles of the gas is 1.31 mol.