Question

What is the index of refraction for a medium where light has a velocity of 2.75 x108 m/s?1.090.2500.9176.75

Answer 1

In order to solve this, we will use the formula

`n=(c)/(v)`

where n is the index of infraction, c is the speed of light (3x10^8), and v is the medium in which the velocity is measured

solving for n,

n = (3x10^8)/(2.75x10^8) = 1.09