Question

Triangle JKL is similar to Triangle PQR. 12 13 5 K R Q Determine the ratio equivalent to cos Q

Answer 1

Given : Triangle JKL is similar to Triangle PQR.

So, the angle Q is corresponding to the angle K

From the triangle JKL :

`\begin{gathered} \cos K=(adjacent)/(hypotenuse) \\ \\ \cos K=(5)/(13) \\ \\ \cos Q=\cos K=(5)/(13) \end{gathered}`

so, the answer is : the ratio = 5/13