Question

A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track. If the car started from rest at the top of a hill, how much higher was that point on the track than the lowest point? (Use g = 9.80 m/s2, and ignore friction.)

17 m
23 m
34 m
69 m

Answer 1

34 m I just took the quiz

Answer 2

Answer: The correct answer is 34.5 m.

Step-by-step explanation:

The equation of motion is as follows;

`v^(2) -u^(2)= 2as`

Here, v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance.

It is given in the problem that a car starts from rest at the top of a hill. A 440 kg roller coaster car is going 26 m/s when it reaches the lowest point on the track.

`v^(2) -u^(2)= 2gs`

Here, g is the acceleration due to gravity.

Put g= 9.80 m/s^2, u=0 and v= 26 m/s.

`(26)^(2) -(0)^(2)= 2(9.8)s`

`s=(676)/(19.6)`

`s= 34.5 m`

Therefore, the correct answer is 34.5 m.