Answer:
one third
Step-by-step explanation:
F = 2000 N
Initially, masses are m1 and m2 and the distance between the two masses be r.
Now, the masses are changed.
m1' = m1 / 3, m2' = m2 / 3
Let the new distance between the two masses is r'.
F = G m1 x m2 / r^2 ..... (1)
F = G m1' x m2' / r'^2
F = G (m1/3) (m2/3) / r'^2
Substitute the value of F from equation (1)
G m1 x m2 / r^2 = G m1 x m2 / 9 r'^2
By solving we get
r' = r /3
Thus, the distance between them is also one third.