Question

What is simplified form of 7x^2y^3/28xy

Answer 1

`(7x^2y^3)/(28xy)`

Divide 7 by 28:

7/28 = 1/4

To divide the variables, subtract the exponents:

`x^((2-1))y^((3-1))=x^1y^2=xy^2`

SO, the final expression is:

`(1)/(4)xy^2=(xy^2)/(4)`