If ABCD is dilated by a factor of 3, thecoordinate of B' would be:4С3B.2-5-2 -1 0-4نما12.4 53-1A-2D-3B' = ([?], [ ]

Miqdad Ali asked May 2, 2023

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Miqdad Ali asked May 2, 2023

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11 votes

Solution

For this case the origianl coordinate for B is:

B= (-2,2)

After a dilation of factor 3 we got:

B' = (-6, 6)

Steve Niles answered May 8, 2023

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