Question

Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Findthe z-score of a man who is 69.8 inches tall. (to 4 decimal places)

Answer 1

Given:

mean of 69.0 inches and a standard deviation of 2.8 inches.

Required:

Find the z-score of a man who is 69.8 inches tall. (to 4 decimal places

Step-by-step explanation:

`\begin{gathered} z\text{ score is obtained as} \\ \\ z=((x-\mu))/(\sigma)\text{ =}((69.8-69.0))/(2.8)\text{ =0.2857} \end{gathered}`

Required answer:

`z=0.2857`