Question

Wyatt’s eye-level height is 120 ft above sea level, and Shawn’s eye-level height is 270 ft above sea level. How much farther can Shawn see to the horizon? Use the formula mc024-1.jpg, mc024-2.jpg with d being the distance they can see in miles and h being their eye-level height in feet. mc024-3.jpg mi mc024-4.jpg mi mc024-5.jpg mi mc024-6.jpg mi

Answer 1

The answer is 3√5 mi.

The formula is: d = √(3h/2)

Wyatt:
h = 120 ft
d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi

Shawn:
h = 270 ft
d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi

How much farther can Shawn see to the horizon?
Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi