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Simplify open parentheses x to the 4 fifths power close parentheses to the 3 sevenths power.

x to the 7 twelfths power
x to the 12 over 35 power
x to the 13 over 35 power
x to the 43 over 35 power

2 Answers

1 vote
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User Suresh Mahawar
by
8.2k points
3 votes

Answer:


x^(12)/(35)

Explanation:

Here let us first write our expression

It says, x raise to 4 5th power i.e 4 by 5 , again raise to 3 7th power i.e 3 by 7

or
(x^{(4)/(5)})^(3)/(7)

Now in this we apply the rule of product of exponents . The rule is like this.


(x^(m))^(n)=x^(mn)

Let us apply the rule in our problem


(x^{(4)/(5)})^(3)/(7) = x^{(4)/(5)*(3)/(7)}


x^{(4)/(5)*(3)/(7)} = x^{(4*3)/(5*7)}


x^{(4*3)/(5*7)}=x^{(12)/(35)}

Which is x to the 12 over 35 hence our b option is correct

User Jstnchng
by
7.5k points