Which expression is equivalent to g^−m ÷ g^n

asked Mar 10, 2018 234k views

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g^−m ÷ g^n

1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)

Lee Netherton answered Mar 17, 2018

7.3k points