32.1k views
0 votes
How many six digits even numbers are possible if the leftmost digit cannot be zero

User Hardysim
by
6.6k points

1 Answer

4 votes
The easiest way to do this is to write out 6 spaces like this.

_ * _ * _ * _ * _ * _ Now, in each space we need to find how many possible numbers could work.

Since the first space cannot be zero, that leaves us with 2,4,6,8 as even numbers, which is 4 even numbers.

So, we get 4*_*_*_*_*_

In all the other spaces, we CAN use 0 which means there are 5 even numbers. So, we fill in all the other spots and get:
4*5*5*5*5*5

Multiply it out and you get 12,500 different possibilities.
User Srinivasan JV
by
6.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.