Question

Inside a television picture tube there is a build-up of electrons (charge of 1.602 × 10^–19 C) with an average spacing of 38.0 nanometers between electrons. Find the electric field inside the picture tube. (Round to three significant figures.)

Answer 1

The electric field inside the picture tube is 1.75 x 10^10 N/C.

Step-by-step explanation:

The electric field inside the picture tube can be found by dividing the electric force between two neighboring electrons by the charge of one electron:

E = F/q = (k * e^2) / (r^2 * q)

Where:
k is the electrostatic constant (9.0 x 10^9 Nm^2/C^2)
e is the charge of one electron (1.602 x 10^-19 C)
r is the average spacing between electrons (38.0 nm = 3.80 x 10^-8 m)
q is the charge of one electron (1.602 x 10^-19 C)

Substituting the values:
E = (9.0 x 10^9 Nm^2/C^2) * (1.602 x 10^-19 C)^2 / ((3.80 x 10^-8 m)^2 * (1.602 x 10^-19 C))

E = 1.75 x 10^10 N/C

Answer 2

The answer is 997,000 N/C