2 Answers

Corey Quillen · Answer 1 · 2018-04-12T20:52:11+0000

The standard form of a quadratic equation is :

ax² + bx + c = 0

And the quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} .

So, first step is to compare the given equation with the above equation to get the value of a, b and c.

So, a = -1, b = 2 and c = 1.

Next step is to plug in these values in the above formula. Therefore,

$x=(-2\pm√((2)^2-4*(-1)*(1)))/(2*(-1))$

$=(-2\pm√(4+4))/(-2)$

$=(-2\pm√(8))/(-2)$

$=(-2\pm√(4*2))/(-2)$

$=(-2\pm√(4)*√(2))/(-2)$

$=(-2\pm2*√(2))/(-2)$

$=-(-2)/(-2) \pm(2√(2))/(-2)$

So, x =
$1 \pm√(2) .$

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