Question

A ladder that is 32 feet long leans against a building. The angle of elevation of the ladder is 70 degrees. To the nearest tenth of a foot how high off the ground is the top of the ladder?

Answer 1

30×cos(70)=10.26ft
................

Answer 2

Answer: The top of the ladder is 30 feet high off the ground.

Explanation:

Since we have given that

Length of ladder AC = 32 feet

Angle of elevation of the ladder = 70°

We need to find the height of top of the ladder high off the ground i.e. AB.

Consider, Δ ABC,

`\sin 70^\circ=(AB)/(AC)\\\\0.939=(AB)/(32)\\\\0.939* 32=AB\\\\30.07=AB\\\\AB=30\ feet`

Hence, the top of the ladder is 30 feet high off the ground.