Question

How many grams of sodium sulfate (Na2SO4) are there in 0.192 mol?

Answer 1

Answer: There are 27.3 grams of Na2SO4 in 0.192 moles of this compound

Step-by-step explanation:

The question requires us to calculate the amount of sodium sulfate, Na2SO4, that are in 0.192 moles of this compound.

The number of moles of a substance can be calculated from the mass of the sample, in grams, and the molar mass of the substance, in grams per mol:

`n=(m)/(M)`

where n is the number of moles, m is the mass and M is the molar mass.

If we rearrange the equation above, we can calculate the mass of a sample from the number of moles and molar mass of a compound:

`n=(m)/(M)\rightarrow m=n* M`

Thus, in order to calculate the mass of Na2SO4 in 0.192 moles of this compound, we need to determine the molar mass of Na2SO4.

The atomic masses of Na, S and O are 22.99, 32.06 and 15.99 amu. Then we can calculate the molar mass of Na2SO4 as:

`molar\text{ mass Na}_2SO_4=2*22.99+1*32.06+4*15.99=142.0g/mol`

Now that we have the molar mass of Na2SO4 (142.0 g/mol) and the number of moles in the sample (0.192 mol), we can determine the mass of the sample using the previous equation:

`m=n* M\rightarrow m=0.192mol*142.0g/mol=27.3g`

Therefore, there are 27.3 grams of Na2SO4 in 0.192 moles of this compound.