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Find P(A or B), if the events are disjointed. P(A) = 9/25 P(B) = 9/25

1 Answer

4 votes

Answer:
P(A\ or\ B) = (18)/(25)

Explanation:

We know that when two events are disjoint then their intersection is empty.

if A and B are disjoint then
P(\cap B)=0

Also, we know that the probability of getting A or B is given by :


\text{P(A or B)}=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow\ P(\text{A or B})=(9)/(25)+(9)/(25)\\\\\Rightarrow\ P(\text{A or B})=(18)/(25)

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