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If the length of one leg of a right triangle is 16 and the length of the hypotenuse is 2 more than the length of the other leg, what are the lengths of all the sides of the triangle?
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If the length of one leg of a right triangle is 16 and the length of the hypotenuse is 2 more than the length of the other leg, what are the lengths of all the sides of the triangle?

User Max Wolfen
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1 Answer

5 votes
Let the length of one leg be x then another leg is (x+2)

According to Pythagoras theorem,
x^2 + (x+2)^2=16^2
=> x^2 + 2x - 126 =0
=>x= √(126 - 1) = 10.225
By sreedharchaya's formula
User Muhammed Afsal
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5.2k points
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