Question

What volume will 35.9 g of hydrogen gas (H2) occupy at STP?

Answer 1

35.9g x 1 mol/ 2.016g x 22.4 L/ 1 mol= 398.89 L

Answer 2

Answer: 402.08 L

Explanation: According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

`\text{Number of moles}=(35.9 g)/(2g/mol)=17.95moles`

Now 1 mole of
`H_2` molecule occupy= 22.4 L at STP

17.95 moles of
`H_2` molecule contains =
`(22.4)/(1)* 17.95=402.08 L` at STP